Answer 0 azzamr21 Apply the distributive property 2√5 ⋅ 23√7 ⋅ 2 = 4√56√7 or Need a bit more clarification? Step 1 To remove the radicals in the denominator, multiply both the denominator and numerator of the given fraction with a suitable radical Step 2 Make sure that all surds in theSimplify the Following √ 6 √ 2 √ 3 3 √ 2 √ 6 √ 3 − 4 √ 3 √ 6 √ 2 CISCE ICSE Class 9 Question Papers 10 Textbook Solutions Important Solutions 15 Question Bank Solutions
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Simplify 3^-6x(3^4/3^0)^2-How do you simplify 2√36/√33√27?Click here👆to get an answer to your question ️ Simplify 2√(3)3 √(3)6
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Get a highquality answer with stepbystepThe correct option is A3013√6When we multiply these two terms, we get(3√32√2)(2√33√2) = 6√99√64√66√4 = 6(3)13√66(2) = √6 = 3013√6Click here👆to get an answer to your question ️ Simplify 6/2√(3)√(6) √(6)/√(3)√(2) 4√(3)/√(6)√(2)
Let in equilateral ∆ABC, A(1 acos∆ ,2 asin∆), B(1 acosa, 2 asina), C(1 acosß, 2 asinß) and length of median through vertex A is 2b, theAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us CreatorsStudied at Paragon Prep 4 y You multiply the conjugate of the denominator (because of the radical) 6/√32 x √32/√32 (this equals one) It would equal 6√318/3√6√6–4, then you
Solution 2√36/√33√27 = 2√36√3/(√3*√3)3*3√3 = 2√3–2/√39√3 = 9√3 AnswerJust like numbers have factors (2×3=6), expressions have factors ((x2)(x3)=x^25x6) Factoring is the processSolution We know that rationalization factor for 3 2 2 3 and 3 2 are 3 2 2 3 and 3 2 respectively We will multiply numerator and denominator of the given expression 3 2 2 3 3 2
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6/ (3√2) (2√3) = (3√2) (a√3) 6 (3√22√3)/ (3√22√3) (3√22√3) 6 (3√22√3)/ (9×2) (4×3) 6 (3√22√3)/1812 6 (3√22√3)/6 3√22√3 By comparing both sides , (3√2) (2√3)= (3√2) olemakpadu 6√2 /√3 Rationalize the surd (6√2 /√3) * (√3 /√3) = (6√2*√3) / (√3 *√3) = 6√6/3 = 2√6 Option A Still stuck?
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